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Aviation Physics: Measurements, Conversions, and Formulas

Saif Khamis@saif_khamis
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Section 1

Aviation Physics: Measurements, Conversions, and Formulas

STUDY GUIDE

๐ŸŽ“ Aviation Physics Exam - Study Guide

๐Ÿ“– Chapter 1: Measurements

๐Ÿ”‘ Essential Concepts & Formulas

Concept/FormulaDefinition/EquationWhen to Use
SI UnitsStandard units for measurementConsistent measurements
Standard Formaร—10na \times 10^n, where 1 โ‰ค a < 10Representing large/small numbers
Metric Conversion (Length)Kilo, Hecto, Deca, Meter, Deci, Centi, MilliConverting length units
British Engineering System (Length)Inches, feet, yardsConverting length units
PerimeterSum of all sidesFinding the length around a shape
AreaSpace occupied by a 2D shapeCalculating surface area
VolumeSpace occupied by a 3D shapeCalculating space occupied
MassAmount of matterMeasuring quantity of matter
TimeDuration of eventsMeasuring duration
Speedspeed=distancetimespeed = \frac{distance}{time}Measuring how fast an object moves
Great CircleShortest distance on a sphereNavigation
Temperature ConversionTC=59(TFโˆ’32)T_C = \frac{5}{9}(T_F - 32), TK=TC+273.15T_K = T_C + 273.15Converting temperature scales

๐Ÿ› ๏ธ Problem Types

Type A: Converting to Standard Form

Setup: "When you see a number that is very large or very small."

Method: Move the decimal point until there is only one non-zero digit to the left of the decimal point. Multiply by 10 raised to the power of the number of places the decimal point was moved.

Example: 5300000 = 5.3 x 10^6

Type B: Converting Length Units

Setup: "If given a length in one unit and asked to convert it to another unit."

Method: Use the appropriate conversion factor. For example, to convert meters to kilometers, divide by 1000.

Example: 5000 meters = 5 kilometers

๐Ÿงฎ Solved Example

Problem: Convert 25ยฐC to Fahrenheit. Steps:

  1. Use the formula: TF=95TC+32T_F = \frac{9}{5}T_C + 32
  2. Substitute TC=25T_C = 25: TF=95(25)+32T_F = \frac{9}{5}(25) + 32
  3. Calculate: TF=45+32=77T_F = 45 + 32 = 77
"
โœ…
Answer: 77ยฐF
Section 2

๐Ÿ“– Chapter 2: Kinematics

๐Ÿ”‘ Essential Concepts & Formulas

Concept/FormulaDefinition/EquationWhen to Use
ScalarMagnitude onlyDescribing quantities without direction
VectorMagnitude and directionDescribing quantities with direction
DistanceTotal path lengthScalar quantity
DisplacementChange in positionVector quantity
Speedspeed=distancetimespeed = \frac{distance}{time}Scalar quantity
Velocityvelocity=displacementtimevelocity = \frac{displacement}{time}Vector quantity
Accelerationacceleration=changeย inย velocitytimeacceleration = \frac{change\ in\ velocity}{time}Rate of change of velocity
Uniform Acceleration Equationsv=u+atv = u + at, s=ut+12at2s = ut + \frac{1}{2}at^2, v2=u2+2asv^2 = u^2 + 2asSolving motion problems with constant acceleration

๐Ÿ› ๏ธ Problem Types

Type A: Calculating Displacement

Setup: "When an object moves in multiple directions."

Method: Resolve the motion into components, then calculate the net displacement.

Example: An object moves 3m East, then 4m North. Displacement = 5m Northeast.

Type B: Using Equations of Motion

Setup: "Given initial velocity, acceleration, and time, find the final velocity."

Method: Use the equation v=u+atv = u + at.

Example: u=5m/su = 5 m/s, a=2m/s2a = 2 m/s^2, t=3st = 3 s. v=5+(2)(3)=11m/sv = 5 + (2)(3) = 11 m/s.

๐Ÿงฎ Solved Example

Problem: A car accelerates from rest at 3 m/sยฒ for 5 seconds. What is its final velocity? Steps:

  1. Use the formula: v=u+atv = u + at
  2. Substitute u=0u = 0, a=3a = 3, t=5t = 5: v=0+(3)(5)v = 0 + (3)(5)
  3. Calculate: v=15v = 15
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โœ…
Answer: 15 m/s

๐Ÿ“– Chapter 3: Newton's Laws of Motion

๐Ÿ”‘ Essential Concepts & Formulas

Concept/FormulaDefinition/EquationWhen to Use
Newton's First LawInertia: Object at rest stays at rest, object in motion stays in motionUnderstanding motion without net force
Newton's Second LawF=maF = maCalculating force, mass, or acceleration
Newton's Third LawAction-reaction pairsUnderstanding forces between interacting objects
WeightW=mgW = mgCalculating the force of gravity on an object

๐Ÿ› ๏ธ Problem Types

Type A: Calculating Force

Setup: "Given mass and acceleration, find the force."

Method: Use the equation F=maF = ma.

Example: m=10kgm = 10 kg, a=2m/s2a = 2 m/s^2. F=(10)(2)=20NF = (10)(2) = 20 N.

Type B: Identifying Action-Reaction Pairs

Setup: "When two objects interact."

Method: Identify the force exerted by the first object on the second, and the equal and opposite force exerted by the second object on the first.

Example: A book on a table. Action: Book exerts force on table. Reaction: Table exerts force on book.

๐Ÿงฎ Solved Example

Problem: A 5 kg object accelerates at 4 m/sยฒ. What is the net force acting on it? Steps:

  1. Use the formula: F=maF = ma
  2. Substitute m=5m = 5, a=4a = 4: F=(5)(4)F = (5)(4)
  3. Calculate: F=20F = 20
"
โœ…
Answer: 20 N

๐Ÿ“– Chapter 4: Falling Bodies

๐Ÿ”‘ Essential Concepts & Formulas

Concept/FormulaDefinition/EquationWhen to Use
Free FallMotion under gravity onlyIdealized falling motion
Acceleration due to gravity (g)gโ‰ˆ9.8m/s2g \approx 9.8 m/s^2Acceleration in free fall
Terminal VelocityConstant velocity when air resistance equals weightFalling with air resistance
Kinematic Equationsv=u+gtv = u + gt, s=ut+12gt2s = ut + \frac{1}{2}gt^2, v2=u2+2gsv^2 = u^2 + 2gsSolving free fall problems

๐Ÿ› ๏ธ Problem Types

Type A: Calculating Final Velocity in Free Fall

Setup: "An object is dropped from a certain height."

Method: Use the equation v=u+gtv = u + gt.

Example: u=0u = 0, g=9.8m/s2g = 9.8 m/s^2, t=4st = 4 s. v=0+(9.8)(4)=39.2m/sv = 0 + (9.8)(4) = 39.2 m/s.

Type B: Calculating Distance in Free Fall

Setup: "An object falls for a certain time."

Method: Use the equation s=ut+12gt2s = ut + \frac{1}{2}gt^2.

Example: u=0u = 0, g=9.8m/s2g = 9.8 m/s^2, t=4st = 4 s. s=0+12(9.8)(42)=78.4ms = 0 + \frac{1}{2}(9.8)(4^2) = 78.4 m.

๐Ÿงฎ Solved Example

Problem: An object is dropped from a height and falls for 3 seconds. How far does it fall? Steps:

  1. Use the formula: s=ut+12gt2s = ut + \frac{1}{2}gt^2
  2. Substitute u=0u = 0, g=9.8g = 9.8, t=3t = 3: s=0+12(9.8)(32)s = 0 + \frac{1}{2}(9.8)(3^2)
  3. Calculate: s=44.1s = 44.1
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โœ…
Answer: 44.1 m

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