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CFA Level 1 - Cheatsheet

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Section 1

CFA Level 1 - Cheatsheet

STUDY GUIDE

๐ŸŽ“ CFA Level 1 - Study Guide

๐Ÿ“‹ Course Structure

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๐Ÿ“š CFA Level 1 โ”œโ”€โ”€ ๐Ÿ“– Chapter 1: Propositional Logic โ”‚ โ”œโ”€โ”€ ๐Ÿ”น Propositions and Logical Operators โ”‚ โ”œโ”€โ”€ ๐Ÿ”น Precedence Rules and Compound Propositions โ”‚ โ”œโ”€โ”€ ๐Ÿ”น Logical Equivalence and Truth Tables โ”‚ โ””โ”€โ”€ ๐Ÿ”น Other Logical Operators โ”œโ”€โ”€ ๐Ÿ“– Chapter 2: Boolean Algebra โ”‚ โ”œโ”€โ”€ ๐Ÿ”น Laws of Boolean Algebra โ”‚ โ”œโ”€โ”€ ๐Ÿ”น Simplifications and Substitution Laws โ”‚ โ””โ”€โ”€ ๐Ÿ”น Functional Completeness โ”œโ”€โ”€ ๐Ÿ“– Chapter 3: Logic Circuits โ”‚ โ”œโ”€โ”€ ๐Ÿ”น Logic Gates โ”‚ โ”œโ”€โ”€ ๐Ÿ”น Combining Gates and Combinatorial Logic Circuits โ”‚ โ””โ”€โ”€ ๐Ÿ”น Disjunctive Normal Form (DNF) โ”œโ”€โ”€ ๐Ÿ“– Chapter 4: Predicate Logic โ”‚ โ”œโ”€โ”€ ๐Ÿ”น Predicates and Domains of Discourse โ”‚ โ”œโ”€โ”€ ๐Ÿ”น Quantifiers โ”‚ โ””โ”€โ”€ ๐Ÿ”น DeMorgan's Laws for Predicate Logic โ”œโ”€โ”€ ๐Ÿ“– Chapter 5: Deduction โ”‚ โ”œโ”€โ”€ ๐Ÿ”น Valid Arguments and Rules of Inference โ”‚ โ””โ”€โ”€ ๐Ÿ”น Formal Proofs and Counterexamples โ””โ”€โ”€ ๐Ÿ“– Chapter 6: Ethical and Professional Standards in Investment Management โ”œโ”€โ”€ ๐Ÿ”น Conflicts of Interest โ”œโ”€โ”€ ๐Ÿ”น Material Nonpublic Information โ”œโ”€โ”€ ๐Ÿ”น Fair Dealing and Priority of Transactions โ””โ”€โ”€ ๐Ÿ”น Responsibilities of Supervisors and Compliance
Section 2

๐Ÿ“– Chapter 1: Propositional Logic

What this chapter covers: This chapter introduces the basic building blocks of logic: propositions and logical operators. It explains how to combine propositions to form compound statements, the rules that govern the order of operations, and how to determine if two statements are logically equivalent using truth tables. The chapter also covers additional logical operators beyond the basic AND, OR, and NOT.

๐Ÿ”‘ Essential Concepts & Formulas

Concept/FormulaDefinition/EquationWhen to UseQuick Check
PropositionA statement that is either true or false.Identifying valid logical arguments.Check if the statement can be assigned a truth value.
Conjunction (AND)pโˆงqp \land qWhen both p and q must be true.Check if both propositions are true in the given scenario.
Disjunction (OR)pโˆจqp \lor qWhen at least one of p or q must be true.Check if at least one proposition is true in the given scenario.
Negation (NOT)ยฌp\neg pWhen the opposite of p is required.Check if the proposition is false in the given scenario.
Conditional (Implication)pโ†’qp \to qTo express "if p, then q".Verify that pp being true implies qq is also true.
Biconditional (Equivalence)pโ†”qp \leftrightarrow qTo express "p if and only if q".Verify that pp and qq have the same truth value.

๐Ÿ› ๏ธ Problem Types

Type A: Evaluating Compound Propositions

Setup: "Given the truth values of individual propositions, determine the truth value of a complex logical statement involving multiple operators."

Method: "Apply precedence rules (NOT, AND, OR) and truth tables for each operator to systematically evaluate the expression."

Final Answer
Example: "If pp is true, qq is false, and rr is true, what is the truth value of (pโˆงq)โˆจยฌr(p \land q) \lor \neg r?" Solution: (TโˆงF)โˆจยฌT=FโˆจF=F(T \land F) \lor \neg T = F \lor F = F.

Type B: Determining Logical Equivalence

Setup: "Determine whether two logical expressions are equivalent by constructing truth tables for both and comparing the results."

Method: "Create truth tables for each expression, listing all possible combinations of truth values for the variables. If the final columns of the truth tables are identical, the expressions are equivalent."

Example: "Are pโ†’qp \to q and ยฌpโˆจq\neg p \lor q logically equivalent? Construct truth tables to verify."

๐Ÿงฎ Solved Example

Problem: Determine the truth value of the proposition (pโˆงq)โ†’(pโˆจq)(p \land q) \to (p \lor q) when pp is false and qq is true.

Given: p=Fp = F, q=Tq = T

Steps:

  1. Evaluate pโˆงqp \land q: FโˆงT=FF \land T = F
  2. Evaluate pโˆจqp \lor q: FโˆจT=TF \lor T = T
  3. Evaluate (pโˆงq)โ†’(pโˆจq)(p \land q) \to (p \lor q): Fโ†’T=TF \to T = T
"
โœ…
Answer: The truth value is True.

โš ๏ธ Common Mistakes

โŒ Mistake 1: Incorrectly applying precedence rules.

โœ… How to avoid: Always remember the order: NOT, AND, OR. Use parentheses for clarity.

โŒ Mistake 2: Confusing conditional and biconditional operators.

โœ… How to avoid: Remember that pโ†’qp \to q is only false when pp is true and qq is false, while pโ†”qp \leftrightarrow q is true only when pp and qq have the same truth value.

๐Ÿ’ก Study Tip

Practice constructing truth tables for various logical expressions. This will help you understand the behavior of different operators and identify logical equivalences.

๐Ÿ“– Chapter 2: Boolean Algebra

What this chapter covers: This chapter introduces the rules and laws of Boolean algebra, which are used to simplify and manipulate logical expressions. It covers important laws such as DeMorgan's laws, distributive laws, and identity laws. The chapter also discusses the concept of functional completeness, which relates to the minimum set of operators needed to express any logical function.

๐Ÿ”‘ Essential Concepts & Formulas

Concept/FormulaDefinition/EquationWhen to UseQuick Check
Double Negationยฌ(ยฌp)=p\neg(\neg p) = pSimplifying expressions with nested negations.Verify by constructing a truth table.
DeMorgan's Lawยฌ(pโˆงq)=ยฌpโˆจยฌq\neg(p \land q) = \neg p \lor \neg q ยฌ(pโˆจq)=ยฌpโˆงยฌq\neg(p \lor q) = \neg p \land \neg qSimplifying negated compound propositions.Verify by constructing a truth table.
Distributive Lawpโˆง(qโˆจr)=(pโˆงq)โˆจ(pโˆงr)p \land (q \lor r) = (p \land q) \lor (p \land r) pโˆจ(qโˆงr)=(pโˆจq)โˆง(pโˆจr)p \lor (q \land r) = (p \lor q) \land (p \lor r)Expanding or factoring logical expressions.Verify by constructing a truth table.
Identity LawpโˆงT=pp \land T = p pโˆจF=pp \lor F = pSimplifying expressions involving true or false.Substitute values to confirm.
Excluded Middlepโˆจยฌp=Tp \lor \neg p = TProving tautologies.Always true, regardless of pp.
Contradictionpโˆงยฌp=Fp \land \neg p = FProving contradictions.Always false, regardless of pp.

๐Ÿ› ๏ธ Problem Types

Type A: Simplifying Boolean Expressions

Setup: "Given a complex Boolean expression, use the laws of Boolean algebra to reduce it to its simplest form."

Method: "Apply DeMorgan's laws, distributive laws, identity laws, and other Boolean algebra rules to systematically simplify the expression."

Final Answer
Example: "Simplify the expression ยฌ(pโˆงยฌq)โˆจq\neg (p \land \neg q) \lor q." Solution: ยฌ(pโˆงยฌq)โˆจq=(ยฌpโˆจยฌ(ยฌq))โˆจq=(ยฌpโˆจq)โˆจq=ยฌpโˆจ(qโˆจq)=ยฌpโˆจq\neg (p \land \neg q) \lor q = (\neg p \lor \neg (\neg q)) \lor q = (\neg p \lor q) \lor q = \neg p \lor (q \lor q) = \neg p \lor q.

Type B: Proving Logical Equivalences using Boolean Algebra

Setup: "Prove that two logical expressions are equivalent by transforming one expression into the other using Boolean algebra laws."

Method: "Start with one expression and apply Boolean algebra laws step-by-step until it is identical to the other expression."

Final Answer
Example: "Prove that pโ†’qp \to q is equivalent to ยฌpโˆจq\neg p \lor q using Boolean algebra." Solution: pโ†’q=ยฌpโˆจqp \to q = \neg p \lor q.

๐Ÿงฎ Solved Example

Problem: Simplify the Boolean expression (pโˆงq)โˆจ(pโˆงยฌq)(p \land q) \lor (p \land \neg q).

Given: Expression: (pโˆงq)โˆจ(pโˆงยฌq)(p \land q) \lor (p \land \neg q)

Steps:

  1. Apply the distributive law: pโˆง(qโˆจยฌq)p \land (q \lor \neg q)
  2. Apply the excluded middle law: pโˆงTp \land T
  3. Apply the identity law: pp
"
โœ…
Answer: pp

โš ๏ธ Common Mistakes

โŒ Mistake 1: Incorrectly applying DeMorgan's laws.

โœ… How to avoid: Remember to negate both propositions and change the operator (AND to OR, OR to AND).

โŒ Mistake 2: Forgetting to apply the distributive law correctly.

โœ… How to avoid: Ensure that you distribute the term to both propositions inside the parentheses.

๐Ÿ’ก Study Tip

Practice simplifying various Boolean expressions. This will help you become familiar with the different laws and how to apply them effectively.

๐Ÿ“– Chapter 3: Logic Circuits

What this chapter covers: This chapter bridges the gap between propositional logic and digital electronics by introducing logic gates, which are the fundamental building blocks of logic circuits. It explains how these gates (AND, OR, NOT) implement logical operations and how they can be combined to create more complex circuits. The chapter also covers combinatorial logic circuits and the concept of disjunctive normal form (DNF).

๐Ÿ”‘ Essential Concepts & Formulas

Concept/FormulaDefinition/EquationWhen to UseQuick Check
AND GateOutput is 1 only if all inputs are 1.Implementing logical conjunction.Verify output for all possible input combinations.
OR GateOutput is 1 if at least one input is 1.Implementing logical disjunction.Verify output for all possible input combinations.
NOT GateOutput is the inverse of the input.Implementing logical negation.Verify output for both possible input values.
Combinatorial CircuitA circuit with no feedback loops.Designing circuits for logical functions.Ensure no output depends on a previous state.
Disjunctive Normal Form (DNF)A disjunction of conjunctions.Representing any truth table as a circuit.Verify that the DNF expression matches the truth table.

๐Ÿ› ๏ธ Problem Types

Type A: Designing Logic Circuits from Boolean Expressions

Setup: "Given a Boolean expression, design a logic circuit that implements the expression using AND, OR, and NOT gates."

Method: "Break down the expression into smaller parts and implement each part with the appropriate gate. Connect the gates according to the structure of the expression."

Example: "Design a logic circuit for the expression (AโˆงB)โˆจยฌC(A \land B) \lor \neg C."

Type B: Determining the Boolean Expression for a Logic Circuit

Setup: "Given a logic circuit, determine the Boolean expression that the circuit implements."

Method: "Trace the circuit from the inputs to the output, writing down the expression for each gate. Combine the expressions according to the connections in the circuit."

Final Answer
Example: "Determine the Boolean expression for a circuit with inputs A, B, and C, where A and B are inputs to an AND gate, and the output of the AND gate and C are inputs to an OR gate." Solution: (AโˆงB)โˆจC(A \land B) \lor C.

๐Ÿงฎ Solved Example

Problem: Design a logic circuit for the Boolean expression (AโˆจB)โˆงยฌC(A \lor B) \land \neg C.

Given: Expression: (AโˆจB)โˆงยฌC(A \lor B) \land \neg C

Steps:

  1. Implement AโˆจBA \lor B using an OR gate with inputs A and B.
  2. Implement ยฌC\neg C using a NOT gate with input C.
  3. Implement (AโˆจB)โˆงยฌC(A \lor B) \land \neg C using an AND gate with the outputs of the OR and NOT gates as inputs.
"
โœ…
Answer: A circuit with an OR gate for A and B, a NOT gate for C, and an AND gate combining the outputs.

โš ๏ธ Common Mistakes

โŒ Mistake 1: Incorrectly connecting logic gates.

โœ… How to avoid: Carefully trace the connections and ensure they match the Boolean expression.

โŒ Mistake 2: Misunderstanding the behavior of logic gates.

โœ… How to avoid: Review the truth tables for AND, OR, and NOT gates.

๐Ÿ’ก Study Tip

Practice converting between Boolean expressions and logic circuits. This will help you understand the relationship between logic and hardware.

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